Hi guys,
I might have mentioned I'm studying an electronics apprenticeship at the moment. I have a problem where I am trying to solve a circuit using Kirchhoff's law but my teacher really hasn't shown me anything but he's expecting me to work it out, I've been looking online including youtube guides to try and find a straight-forward way of solving the circuit, but I just can't find anything in a similar configuration where I can understand.
I've attached the circuit I'm trying to solve, I know it's not an easy thing so I'm not really expecting anyone to take the time to help me out with it, but I just thought I'd ask just in case someone wants to help me out.
Thanks,
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Kirchhoff's law, help :)
Re: Kirchhoff's law, help :)
Google "Kirchhoff's Law Two batteries" and you find lots of examples exactly this configuration.
Senior Principal ASIC Engineer - SystemVerilog, VHDL
Thalion Webshrine - http://thalion.atari.org
ST,STf,STfm,STe,MegaST,MegaSTe,Falcon060
A500+,A600,A4000/060,CD32,CDTV
Thalion Webshrine - http://thalion.atari.org
ST,STf,STfm,STe,MegaST,MegaSTe,Falcon060
A500+,A600,A4000/060,CD32,CDTV
Re: Kirchhoff's law, help :)
Ok will do, thanks 
Re: Kirchhoff's law, help :)
Been a while since I have had to use Kirchoff's laws but if you look at a couple of the voltage loops and one current split you should be able to combine these 3 equations via substitution to work out the answers.
Off the top of my head looking at the circuit:
I'll use x instead of I for the current for a little more clarity:
x1 = x2 + x3
5 - (x1)(4.7K) - (x3)(13.28K) = 0
5 - (x1)(4.7K) -10 -(x2)(6.8K) = 0
Off the top of my head looking at the circuit:
I'll use x instead of I for the current for a little more clarity:
x1 = x2 + x3
5 - (x1)(4.7K) - (x3)(13.28K) = 0
5 - (x1)(4.7K) -10 -(x2)(6.8K) = 0
Life is really simple, but we insist on making it complicated - Confucius

